Two pages(page a, page b) are developed by ajax and use the same url.

By clicking a button on page a, you can navigate to page b. How can you get the page b's content after

firing onclick event on page a by using addNavigationListener or other eventListener?

Here is an example. The source-code is below:

WebBrowser browser = new IEAutomation();

((IEAutomation)browser).setVisible(true);

browser.navigate("http://www.giannifrey.com/ajax/news.html");

browser.waitReady();

Thread.sleep(5000);

HTMLElement element = (HTMLElement)browser.getDocument().getElementById("btn_next");

element.click();

browser.addNavigationListener(new NavigationEventAdapter() {

public void documentCompleted(WebBrowser webBrowser, String url) {

    System.out.println(url);

    String c = webBrowser.getContent();

    //to find whether the browser has loaded the second article' content(contains "willkommen").

    //if loaded, print it.

if (c.contains("willkommen")) {

      System.out.println(c);

    }

}

});I use NavigationEventAdapter in the above code, but I can never prints the second article's content.

Here supplies some additional information:

1.The site http://www.giannifrey.com/ajax/news.html is developed by ajax.I think this is very important.

2.I use Thread.sleep(5000) to load the first page's content into browser and then I can

click on the button ">"(represents by the id:btn_next) to navigate to the page that

shows the second article's content.

3.All the pages in this site uses the same url.This is also very important.

Would you please do me a favor to print the second article's content not by using "Thread.sleep()" but by using addNavigationListener or other eventListener?I also supply the java file of the code in attached files.